Do by tens.
I start at 10. If it cracks, I try 1-9. If it doesn’t crack I go to 20,30,40... max this would need is get till 90 plus 91-100 so 19 max. Do you want less?
Last edited by ExtraCredit on Tue, Oct 20 2020, 9:32 pm; edited 1 time in total
So if you start at 50 and it breaks, how would you proceed? I need a strategy using the minimum amount of attempts regardless of the outcome.
Could it be you meant "What is the maximum number of attempts I might need to find out which floor the breaking floor is, regardless where it is?
And could it be the answer is
Hidden:
18
Hidden:
First, I try the 10th floor. Either the first bulb breaks, then I try floors 1-9 wth the secon bulb, this would be 10 tries if it's floor 9 or 10
Or the first bulb doesn't break. Then I try 20... if it breaks, same as above, this would be 11 tries (if it was floor 19 or 20)
The worst combination would be if it was floor 89 or 90, and this would require 9 attempts with the first bulb to get up to floor 90 plus 9 attempts with the second bulb to get up to floor 89... that would be 18
Could it be you meant "What is the maximum number of attempts I might need to find out which floor the breaking floor is, regardless where it is?
And could it be the answer is
Hidden:
18
Hidden:
First, I try the 10th floor. Either the first bulb breaks, then I try floors 1-9 wth the secon bulb, this would be 10 tries if it's floor 9 or 10
Or the first bulb doesn't break. Then I try 20... if it breaks, same as above, this would be 11 tries (if it was floor 19 or 20)
The worst combination would be if it was floor 89 or 90, and this would require 9 attempts with the first bulb to get up to floor 90 plus 9 attempts with the second bulb to get up to floor 89... that would be 18
Hidden:
I wrote the same answer but wrote 19 to include 100. But you’re right I don’t need to try once I know for sure it’s 100. But your explanation goes till 90. Why not 100?
Could it be you meant "What is the maximum number of attempts I might need to find out which floor the breaking floor is, regardless where it is?
And could it be the answer is
Hidden:
18
Hidden:
First, I try the 10th floor. Either the first bulb breaks, then I try floors 1-9 wth the secon bulb, this would be 10 tries if it's floor 9 or 10
Or the first bulb doesn't break. Then I try 20... if it breaks, same as above, this would be 11 tries (if it was floor 19 or 20)
The worst combination would be if it was floor 89 or 90, and this would require 9 attempts with the first bulb to get up to floor 90 plus 9 attempts with the second bulb to get up to floor 89... that would be 18
You and ExtraCredit both have the same answer.....you're getting warmer, but still not the correct answer.
If you are really asking "what is the minimum number of attempts I need?", then the answer would be 1, but it depend on the floor in question being the first floor (and me trying the first floor first),
I wrote the same answer but wrote 19 to include 100. But you’re right I don’t need to try once I know for sure it’s 100. But your explanation goes till 90. Why not 100?
Hidden:
If the first bulb doesn't break on floor 90, I still have 2 bulbs left... So I go to 95 or 93... and I would need maximum 14 attempts
If you are really asking "what is the minimum number of attempts I need?", then the answer would be 1, but it depend on the floor in question being the first floor (and me trying the first floor first),
I'm all confused now with the wording, but you know what I mean...I need to know in how many attempts I will definitely know which floor. It's possible in less than 18.
I'm all confused now with the wording, but you know what I mean...I need to know in how many attempts I will definitely know which floor. It's possible in less than 18.
Yea I don’t get chaniemommys question either. We are trying to find out what would be the minimum amount of tries necessary.
Last edited by ExtraCredit on Tue, Oct 20 2020, 9:52 pm; edited 1 time in total
