The premise is that they eat the same amount every day... no tricks about winter, summer, grass, hay, calf, no calf, milk, no milk, bigger herd, smaller herd... nothing like this...
And it is a reality: there is one month where they eat less...
Hint2:
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It's about the common civic (gregorian) calendar, it would not work with the jewish calendar...
Hint 3
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It would also work with the Julian calendar
Last edited by ChanieMommy on Tue, Oct 20 2020, 7:44 pm; edited 1 time in total
The premise is that they eat the same amount every day... no tricks about winter, summer, grass, hay, calf, no calf, milk, no milk, bigger herd, smaller herd... nothing like this...
And it is a reality: there is one month where they eat less...
Oh haaaa
Hidden:
February
And I was thinking which month has the moo or hay sound in it...
You are living in a 100-floor apartment building. You know that there is one floor in the building, such that if you drop a light bulb from there or anywhere higher, it will crash upon hitting the ground. If you drop a light bulb from any floor underneath it however, the light bulb will remain intact. If you have two light bulbs at your disposal, what is the minimum amount of drop attempts do you need such that you can surely find which the floor in question is?
You are living in a 100-floor apartment building. You know that there is one floor in the building, such that if you drop a light bulb from there or anywhere higher, it will crash upon hitting the ground. If you drop a light bulb from any floor underneath it however, the light bulb will remain intact. If you have two light bulbs at your disposal, what is the minimum amount of drop attempts do you need such that you can surely find which the floor in question is?
Could it be you mean maximum number?
And could it be the answer is
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18
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First, I try the 10th floor. Either the first bulb breaks, then I try floors 1-9 wth the secon bulb, this would be 10 tries if it's floor 9 or 10
Or the first bulb doesn't break. Then I try 20... if it breaks, same as above, this would be 11 tries (if it was floor 19 or 20)
The worst combination would be if it was floor 89 or 90, and this would require 9 attempts with the first bulb to get up to floor 90 plus 9 attempts with the second bulb to get up to floor 89... that would be 18
Last edited by ChanieMommy on Tue, Oct 20 2020, 9:34 pm; edited 2 times in total
You are living in a 100-floor apartment building. You know that there is one floor in the building, such that if you drop a light bulb from there or anywhere higher, it will crash upon hitting the ground. If you drop a light bulb from any floor underneath it however, the light bulb will remain intact. If you have two light bulbs at your disposal, what is the minimum amount of drop attempts do you need such that you can surely find which the floor in question is?
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50, You drop the first on the 50th floor. If it cracks you start on floor 1 and might need to go till 49. If it doesn’t crack you start your way up from 51-99
I first would make an estimate from which floor on it breaks and drop it from the floor underneaht... If the bulb remains intact, I am lucky and I can start trying from there, going one floor higher for each drop, till it breaks...
If I am unlucky and first bulb breaks, I would have to start from the bottom and go up uptill it breaks...
I woud not try the 50th floor first, because this seems unrealistic... 4th floor could maybe seem realistic...
If the riddle has nothing to do with reality, and there is an equal probality for every floor, I might start at 50...
Anyway, the minimum number of tries would be the floor from which it breaks plus one if I am unlucky, and the floor from which it breaks minus the floor from which I tried plus one if I m lucky
So if you start at 50 and it breaks, how would you proceed? I need a strategy using the minimum amount of attempts regardless of the outcome.
I first would make an estimate from which floor on it breaks and drop it from the floor underneaht... If the bulb remains intact, I am lucky and I can start trying from there, going one floor higher for each drop, till it breaks...
If I am unlucky and first bulb breaks, I would have to start from the bottom and go up uptill it breaks...
I woud not try the 50th floor first, because this seems unrealistic... 4th floor could maybe seem realistic...
If the riddle has nothing to do with reality, and there is an equal probality for every floor, I might start at 50...
Anyway, the minimum number of tries would be the floor from which it breaks plus one if I am unlucky, and the floor from which it breaks minus the floor from which I tried plus one if I m lucky
I wrote my megilla while you wrote yours. Don’t understand your answer though.
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Why not start at 50? Isn’t it least risky to start at 50? Any other floor might make you need to try more than 50. If you start with the 4th you might need to go till 97.
