Maybe when our math teachers wake up, they can be of assistance.
Ok I’m on to something.
Hidden:
If there are 2 then I know the answer. When the plane arrives and no one boards the blue eyed guys both chop they must have blue eyes. Because they think if I’d have brown as well then the blue eyed would only see brown, must be there are at least 2. So if he only sees 1 he knows he’s the second. So both board I guess the next day. Now how do I translate this to 60/40?
If there are 2 then I know the answer. When the plane arrives and no one boards the blue eyed guys both chop they must have blue eyes. Because they think if I’d have brown as well then the blue eyed would only see brown, must be there are at least 2. So if he only sees 1 he knows he’s the second. So both board I guess the next day. Now how do I translate this to 60/40?
Hidden:
It's the same, but you have to wait till day 40, and then they suddenly all want to board the plane at once...
Why on earth should it take 40 days for them to come to this conclusion? What changed their mind on the 40th day that couldn’t happen on the 4th?
Hidden:
Like you said, if there were 2 ppl, they each wait to see if the other one leaves on day 1, if not they know they’re blue too, so they both leave on day 2.
Now take a 3rd blue one in the picture. Each of them see 2 blue eyed ppl. So assuming first that they themselves are not blue, they wait two days to see if they leave, like it should it happen were there 2 ppl. If they don’t leave, then they know they’re blue and all end up leaving on day 3.
4 the person: seeing 3 ppl, they should be leaving on day 3 like above cheshbon. If they don’t leave, then they’ll all end up leaving on day 4......
And so on so forth.....
Like you said, if there were 2 ppl, they each wait to see if the other one leaves on day 1, if not they know they’re blue too, so they both leave on day 2.
Now take a 3rd blue one in the picture. Each of them see 2 blue eyed ppl. So assuming first that they themselves are not blue, they wait two days to see if they leave, like it should it happen were there 2 ppl. If they don’t leave, then they know they’re blue and all end up leaving on day 3.
4 the person: seeing 3 ppl, they should be leaving on day 3 like above cheshbon. If they don’t leave, then they’ll all end up leaving on day 4......
And so on so forth.....
Oh ok the bolded helped me get it. Good one! So do I get at least partial extra credit for figuring out the first part?
Another question
Hidden:
why can’t they figure this out the second day vs the 40th? They do know From the beginning that there are either 39 or 40 blue eyed. Why do 39 days have to pass till they figure it out? I do have a feeling they all left the second day
Oh ok the bolded helped me get it. Good one! So do I get at least partial extra credit for figuring out the first part?
Another question
Hidden:
why can’t they figure this out the second day vs the 40th? They do know From the beginning that there are either 39 or 40 blue eyed. Why do 39 days have to pass till they figure it out? I do have a feeling they all left the second day
Sorry, then you didn’t fully grasp the concept yet...
Sorry, then you didn’t fully grasp the concept yet...
I did but
Hidden:
the example you’re giving is as if they find out every day that the amount of blue eyed are going up with one. Your example states that Day 2 they see that 2 didn’t leave so they know it’s 3 etc. Here on day one all blue eyed see 39 blue and 60 brown. Why do they have to wait 39 days to figure out if they have blue too? It’s never a question of anything less than 39. It’s 39 or 40. Having a hard time understanding why so many days need to pass till they come to this conclusion.
the example you’re giving is as if they find out every day that the amount of blue eyed are going up with one. Your example states that Day 2 they see that 2 didn’t leave so they know it’s 3 etc. Here on day one all blue eyed see 39 blue and 60 brown. Why do they have to wait 39 days to figure out if they have blue too? It’s never a question of anything less than 39. It’s 39 or 40. Having a hard time understanding why so many days need to pass till they come to this conclusion.
Hidden:
True, it’s a question between 39 & 40, but what knowledge do they gain BEFORE 39 DAYS?
It’s hard to break down the thought process of so many people, so let’s take an example of only 5 blue eyed people. Suppose you’re one of them, and everyone is made aware that at least one person is blue.
This will be your thought process (granted that you’re a mathematician):
“I see 4 people with blue eyes, A-B-C and D. My first assumption is that I’m NOT blue, and each individual assumes the same. So if my assumption is correct, D sees only A-B and C BUT MORE THAN THIS, he knows that they’re also assuming first that they’re not blue. So If D’s assumption AND mine are correct, and C also assumes he’s not blue, he only sees A and B being blue. If there are two people, both are assuming they’re not blue first, but if no one leaves, then that assumption is proven false. “
Slowly, this chain of thoughts unravels.
Realize that all of these listed below is YOUR thinking process(or what each individual is thinking)
On day 2, Cs assumption is proven false.
On day 3, D’s
On day 4, your own assumption is false, then on day 5 you will all leave.
Sorry if you don’t understand.....I saw this riddle a while ago but didn’t post it cuz I didn’t understand the solution either.....till I did.
True, it’s a question between 39 & 40, but what knowledge do they gain BEFORE 39 DAYS?
It’s hard to break down the thought process of so many people, so let’s take an example of only 5 blue eyed people. Suppose you’re one of them, and everyone is made aware that at least one person is blue.
This will be your thought process (granted that you’re a mathematician):
“I see 4 people with blue eyes, A-B-C and D. My first assumption is that I’m NOT blue, and each individual assumes the same. So if my assumption is correct, D sees only A-B and C BUT MORE THAN THIS, he knows that they’re also assuming first that they’re not blue. So If D’s assumption AND mine are correct, and C also assumes he’s not blue, he only sees A and B being blue. If there are two people, both are assuming they’re not blue first, but if no one leaves, then that assumption is proven false. “
Slowly, this chain of thoughts unravels.
Realize that all of these listed below is YOUR thinking process(or what each individual is thinking)
On day 2, Cs assumption is proven false.
On day 3, D’s
On day 4, your own assumption is false, then on day 5 you will all leave.
Sorry if you don’t understand.....I saw this riddle a while ago but didn’t post it cuz I didn’t understand the solution either.....till I did.
Hidden:
I understand exactly what you posted here but you keep going back to let’s say there are 3-4-5. You’re not explaining it the way I’m questioning. Why shouldn’t they come to this conclusion on day 2 vs day 40? I guess I just need to think it over a few times till it clicks fully. Ok I’ll do that while I tend to the laundry. Let ya know if and when it clicks.
True, it’s a question between 39 & 40, but what knowledge do they gain BEFORE 39 DAYS?
It’s hard to break down the thought process of so many people, so let’s take an example of only 5 blue eyed people. Suppose you’re one of them, and everyone is made aware that at least one person is blue.
This will be your thought process (granted that you’re a mathematician):
“I see 4 people with blue eyes, A-B-C and D. My first assumption is that I’m NOT blue, and each individual assumes the same. So if my assumption is correct, D sees only A-B and C BUT MORE THAN THIS, he knows that they’re also assuming first that they’re not blue. So If D’s assumption AND mine are correct, and C also assumes he’s not blue, he only sees A and B being blue. If there are two people, both are assuming they’re not blue first, but if no one leaves, then that assumption is proven false. “
Slowly, this chain of thoughts unravels.
Realize that all of these listed below is YOUR thinking process(or what each individual is thinking)
On day 2, Cs assumption is proven false.
On day 3, D’s
On day 4, your own assumption is false, then on day 5 you will all leave.
Sorry if you don’t understand.....I saw this riddle a while ago but didn’t post it cuz I didn’t understand the solution either.....till I did.
I understand exactly what you posted here but you keep going back to let’s say there are 3-4-5. You’re not explaining it the way I’m questioning. Why shouldn’t they come to this conclusion on day 2 vs day 40? I guess I just need to think it over a few times till it clicks fully. Ok I’ll do that while I tend to the laundry. Let ya know if and when it clicks.
Hidden:
Because the logic all starts at 2 people, or actually 1 and builds up.
In the scenario of 5 ppl, they had to wait till day 5, not day 2.
True, it’s a question between 39 & 40, but what knowledge do they gain BEFORE 39 DAYS?
It’s hard to break down the thought process of so many people, so let’s take an example of only 5 blue eyed people. Suppose you’re one of them, and everyone is made aware that at least one person is blue.
This will be your thought process (granted that you’re a mathematician):
“I see 4 people with blue eyes, A-B-C and D. My first assumption is that I’m NOT blue, and each individual assumes the same. So if my assumption is correct, D sees only A-B and C BUT MORE THAN THIS, he knows that they’re also assuming first that they’re not blue. So If D’s assumption AND mine are correct, and C also assumes he’s not blue, he only sees A and B being blue. If there are two people, both are assuming they’re not blue first, but if no one leaves, then that assumption is proven false. “
Slowly, this chain of thoughts unravels.
Realize that all of these listed below is YOUR thinking process(or what each individual is thinking)
On day 2, Cs assumption is proven false.
On day 3, D’s
On day 4, your own assumption is false, then on day 5 you will all leave.
Sorry if you don’t understand.....I saw this riddle a while ago but didn’t post it cuz I didn’t understand the solution either.....till I did.
Something is off?
Why doesn’t C see that D is blue
Everyone should see everyone but themselves
He DOES see it. And that is exactly why it takes till day 5. Because D is assuming he’s NOT blue, C should only be seeing A and B and therefore AB and C should be leaving day 3. But since that doesn’t happen, D now knows that he’s also blue. So if my assumption that I’m not blue is true, ABCD should be leaving day 4. Seeing that doesn’t happen tells me that MY assumption has been wrong and I must also be blue. THAT COULD ONLY HAPPEN AFTER 4 DAYS. And so, the next night we’re all leaving.
right
