Let me know if I’m right cuz I need to do bedtime and I’m too stuck...
Sorry can u look at my original answer since I edited it
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5 races of 5 2 of each group are eliminated
Winners race each other
At this point 2 full groups plus 4 of the 3 rd place holders group are eliminated
7 still in the race
Now race 5
Top 3 race other 2
Let me know if I’m right cuz I need to do bedtime and I’m too stuck...
Sorry can u look at my original answer since I edited it
[/
Hidden:
spoil]8
5 races of 5 2 of each group are eliminated
Winners race each other
At this point 2 full groups plus 4 of the 3 rd place holders group are eliminated
7 still in the race
Now race 5
Top 3 race other 2
After the 5 winners race you know the fastest horse.
The second horse is either the 2 nd winner of the 5 winner race or the 2nd position in the race that the winner came from.
And the 3rd has a choice of 3 so race these 5.
After the 5 winners race you know the fastest horse.
The second horse is either the 2 nd winner of the 5 winner race or the 2nd position in the race that the winner came from.
And the 3rd has a choice of 3 so race these 5.
After racing the 5 winners of each of the 5 races
You know the fastest horse of all
The second place is either the winners first race second place or the winners second race second place
The 3rd place can be (the one who isn’t 2nd place, )the 3 rd place of the winners first race, the third place of the winners second race or the 2nd place of the 2nd place horses original race...
After racing the 5 winners of each of the 5 races
You know the fastest horse of all
The second place is either the winners first race second place or the winners second race second place
The 3rd place can be (the one who isn’t 2nd place, )the 3 rd place of the winners first race, the third place of the winners second race or the 2nd place of the 2nd place horses original race...
The first and second place I get but trying to chap if there can’t be more options in 3rd place. Boy, I’m giving away too much time here lately.
After the 5 winners race you know the fastest horse.
The second horse is either the 2 nd winner of the 5 winner race or the 2nd position in the race that the winner came from.
And the 3rd has a choice of 3 so race these 5.
7 races.
First do 5 races w/ each of 5 different horses. Let's name them races A thru E, with A1 coming in first place in his race, A2 second place etc. like this:
A1 A2 A3 A4 A5
B1 B2 B3 B4 B5
C1 C2 C3 C4 C5
D1 D2 D3 D4 D5
E1 E2 E3 E4 E5
The next race will be A1, B1, C1, D1 and E1, in other words, all first place winners. Suppose the result of this race is A1, B1 and C1 taking 1st, 2nd and 3rd place respectively.
Obviously, all D and E racers are eliminated. C1 came in 3rd, so C2 and C3 who are slower than him are also eliminated. B1 came in 2nd, so B2 might possibly still make it top 3, but B3 will have to be eliminated. A1 came in first, so he's definitely the fastest. He won't need to be in the last race.
So for the last race were only left with A2, A3, B1, B2 and C1.
7 races.
First do 5 races w/ each of 5 different horses. Let's name them races A thru E, with A1 coming in first place in his race, A2 second place etc. like this:
A1 A2 A3 A4 A5
B1 B2 B3 B4 B5
C1 C2 C3 C4 C5
D1 D2 D3 D4 D5
E1 E2 E3 E4 E5
The next race will be A1, B1, C1, D1 and E1, in other words, all first place winners. Suppose the result of this race is A1, B1 and C1 taking 1st, 2nd and 3rd place respectively.
Obviously, all D and E racers are eliminated. C1 came in 3rd, so C2 and C3 who are slower than him are also eliminated. B1 came in 2nd, so B2 might possibly still make it top 3, but B3 will have to be eliminated. A1 came in first, so he's definitely the fastest. He won't need to be in the last race.
So for the last race were only left with A2, A3, B1, B2 and C1.
Very clear solution. I like it!
Pity I didn’t have the time and zitzfleish to figure out myself
7 races.
First do 5 races w/ each of 5 different horses. Let's name them races A thru E, with A1 coming in first place in his race, A2 second place etc. like this:
A1 A2 A3 A4 A5
B1 B2 B3 B4 B5
C1 C2 C3 C4 C5
D1 D2 D3 D4 D5
E1 E2 E3 E4 E5
The next race will be A1, B1, C1, D1 and E1, in other words, all first place winners. Suppose the result of this race is A1, B1 and C1 taking 1st, 2nd and 3rd place respectively.
Obviously, all D and E racers are eliminated. C1 came in 3rd, so C2 and C3 who are slower than him are also eliminated. B1 came in 2nd, so B2 might possibly still make it top 3, but B3 will have to be eliminated. A1 came in first, so he's definitely the fastest. He won't need to be in the last race.
So for the last race were only left with A2, A3, B1, B2 and C1.
Is this how we’ll feel when Moshiach comes and everything will be so simple and clear after we wracked our brains all this time?
Ok ready for the next one.
On the table in front of you there is a square with 4 coins, one at each corner. You are blindfolded and are given the task to turn all of the coins with either heads up or tails up. You may turn however many coins you want, and when you decide, you may ask the person sitting next to you whether all coins are same side up, and you'll be given a yes or no reply. Every time you ask, that's considered a 'turn'. After each turn, the square will be rotated so that you now don't know which coins you flipped.
Question is:
Is it possible to devise a strategy so that after a certain amount of turns you'll definitely achieve your goal, or will you have to continue turn after turn infinitely until luck kicks in?
On the table in front of you there is a square with 4 coins, one at each corner. You are blindfolded and are given the task to turn all of the coins with either heads up or tails up. You may turn however many coins you want, and when you decide, you may ask the person sitting next to you whether all coins are same side up, and you'll be given a yes or no reply. Every time you ask, that's considered a 'turn'. After each turn, the square will be rotated so that you now don't know which coins you flipped.
Question is:
Is it possible to devise a strategy so that after a certain amount of turns you'll definitely achieve your goal, or will you have to continue turn after turn infinitely until luck kicks in?
All my coins are rusty already but ok I’ll try it.
On the table in front of you there is a square with 4 coins, one at each corner. You are blindfolded and are given the task to turn all of the coins with either heads up or tails up. You may turn however many coins you want, and when you decide, you may ask the person sitting next to you whether all coins are same side up, and you'll be given a yes or no reply. Every time you ask, that's considered a 'turn'. After each turn, the square will be rotated so that you now don't know which coins you flipped.
Question is:
Is it possible to devise a strategy so that after a certain amount of turns you'll definitely achieve your goal, or will you have to continue turn after turn infinitely until luck kicks in?
Hidden:
First try
So the options are as follows either it’s 2 and 2 or it’s 1 and 3
If it’s 2 and 2 then one diagonal switch of 2 and one straight switch of 2 and if it’s still not I can do one more diagonal switch .
I think this covers all choices of 2:2.
If this doesn’t work then it’s 1:3 Then flip one coin first, and either win, or continue with the above strategy...
So the options are as follows either it’s 2 and 2 or it’s 1 and 3
If it’s 2 and 2 then one diagonal switch of 2 and one straight switch of 2 and if it’s still not I can do one more diagonal switch .
I think this covers all choices of 2:2.
If this doesn’t work then it’s 1:3 Then flip one coin first, and either win, or continue with the above strategy...
