Sorry to throw a wrench in your riddle, but I just noticed that the man in the other rows is wearing black shoes. The man in the bottom row is wearing the fat brown shoes. But not the black shoes. So you really don’t know the value of the man wearing the brown shoes but minus the black shoes. So the riddle is actually unsolvable.
Sorry to throw a wrench in your riddle, but I just noticed that the man in the other rows is wearing black shoes. The man in the bottom row is wearing the fat brown shoes. But not the black shoes. So you really don’t know the value of the man wearing the brown shoes but minus the black shoes. So the riddle is actually unsolvable.
Maybe he's wearing the brown shoes OVER the black ones!
You have 9 marbles all weighing the same but one. Can you find out which marble weighs more by using a balancing scale twice?
Hidden:
You do 3&3 to find out in which pile of 3 it is. If both are same it’s in the 3 not on scale. Then do 1&1. Whichever weighs less is the one and if both the same it’s the 1 spare
Sorry to throw a wrench in your riddle, but I just noticed that the man in the other rows is wearing black shoes. The man in the bottom row is wearing the fat brown shoes. But not the black shoes. So you really don’t know the value of the man wearing the brown shoes but minus the black shoes. So the riddle is actually unsolvable.
It’s galoshes worn over regular shoes.
Don’t throw wrenches here.
A train from NY to Atlanta takes 12 hours. Trains leave NY bound for Atlanta and also leave Atlanta bound for NY - every hour on the hour. If a person gets onto the noon train in NY heading towards Atlanta, in the 12 hours that he will be sitting on the train until his midnight arrival, how many NY-bound trains will he pass?
The riddle was formulated correctly (when it was explained that the switches are on the outside). I was clapping for the person who got the solution.
I don't know. If there are no other limitations, I try the first button, go in, if the light is on, I stay, if it is not on, I go out again and try the second bottom and go in again. If the light is on now, I stay, if it is still not on, I push the third bottom.
Problem solved.
so where does the solution come in?
There have to be limitations that were not properly formulated.
Turn the first switch on and leave it on for 10 minutes. Then turn it off. Then turn on the second switch and enter the room. If the light is now on - you know it's the second switch. If the light is off, feel the bulb. If it's warm - you know it's the first switch. If none of the above - you know it's the third (untouched) switch.
But who said the number of comings and goings into the room and out of the room was limited?
I don't know. If there are no other limitations, I try the first button, go in, if the light is on, I stay, if it is not on, I go out again and try the second bottom and go in again. If the light is on now, I stay, if it is still not on, I push the third bottom.
Problem solved.
so where does the solution come in?
There have to be limitations that were not properly formulated.
